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11040424000033 is a prime number
BaseRepresentation
bin1010000010101000110010…
…0011001111101000100001
31110002110021010112122111211
42200222030203033220201
52421341242021000113
635251522322110121
72216433666414661
oct240521443175041
943073233478454
1011040424000033
1135772435854aa
1212a385b7ab341
1362115229bbbc
142a25061941a1
151422c04e5b3d
hexa0a8c8cfa21

11040424000033 has 2 divisors, whose sum is σ = 11040424000034. Its totient is φ = 11040424000032.

The previous prime is 11040423999989. The next prime is 11040424000061. The reversal of 11040424000033 is 33000042404011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10882761003409 + 157662996624 = 3298903^2 + 397068^2 .

It is an emirp because it is prime and its reverse (33000042404011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11040424000033 - 241 = 8841400744481 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11040423999968 and 11040424000013.

It is not a weakly prime, because it can be changed into another prime (11040424100033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520212000016 + 5520212000017.

It is an arithmetic number, because the mean of its divisors is an integer number (5520212000017).

Almost surely, 211040424000033 is an apocalyptic number.

It is an amenable number.

11040424000033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11040424000033 is an equidigital number, since it uses as much as digits as its factorization.

11040424000033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 11040424000033 its reverse (33000042404011), we get a palindrome (44040466404044).

The spelling of 11040424000033 in words is "eleven trillion, forty billion, four hundred twenty-four million, thirty-three", and thus it is an aban number.