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11041014001403 is a prime number
BaseRepresentation
bin1010000010101010111110…
…1101111010111011111011
31110002111210020201211020102
42200222233231322323323
52421343444041021103
635252101035550015
72216454422351411
oct240525755727373
943074706654212
1011041014001403
113577516624241
1212a39a52bb30b
136212175a6739
142a25606972b1
151423071dae88
hexa0aafb7aefb

11041014001403 has 2 divisors, whose sum is σ = 11041014001404. Its totient is φ = 11041014001402.

The previous prime is 11041014001363. The next prime is 11041014001429. The reversal of 11041014001403 is 30410041014011.

It is a strong prime.

It is an emirp because it is prime and its reverse (30410041014011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11041014001403 is a prime.

It is not a weakly prime, because it can be changed into another prime (11041014001103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520507000701 + 5520507000702.

It is an arithmetic number, because the mean of its divisors is an integer number (5520507000702).

Almost surely, 211041014001403 is an apocalyptic number.

11041014001403 is a deficient number, since it is larger than the sum of its proper divisors (1).

11041014001403 is an equidigital number, since it uses as much as digits as its factorization.

11041014001403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 11041014001403 its reverse (30410041014011), we get a palindrome (41451055015414).

The spelling of 11041014001403 in words is "eleven trillion, forty-one billion, fourteen million, one thousand, four hundred three".