11041014001481 has 2 divisors, whose sum is σ = 11041014001482. Its totient is φ = 11041014001480.

The previous prime is 11041014001429. The next prime is 11041014001519. The reversal of 11041014001481 is 18410041014011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11040966612025 + 47389456 = 3322795^2 + 6884^2 .

It is a cyclic number.

It is not a de Polignac number, because 11041014001481 - 2³⁰ = 11039940259657 is a prime.

It is a super-2 number, since 2×11041014001481² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11041014001481.

It is not a weakly prime, because it can be changed into another prime (11041014061481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520507000740 + 5520507000741.

It is an arithmetic number, because the mean of its divisors is an integer number (5520507000741).

Almost surely, 2^{11041014001481} is an apocalyptic number.

It is an amenable number.

11041014001481 is a deficient number, since it is larger than the sum of its proper divisors (1).

11041014001481 is an equidigital number, since it uses as much as digits as its factorization.

11041014001481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 512, while the sum is 26.

Adding to 11041014001481 its reverse (18410041014011), we get a palindrome (29451055015492).

The spelling of 11041014001481 in words is "eleven trillion, forty-one billion, fourteen million, one thousand, four hundred eighty-one".