Base | Representation |
---|---|
bin | 10100100100001101… |
… | …11111100011101011 |
3 | 1001111111001011200211 |
4 | 22102012333203223 |
5 | 140103024210243 |
6 | 5023340041551 |
7 | 540420000640 |
oct | 122206774353 |
9 | 31444034624 |
10 | 11041241323 |
11 | 4756547032 |
12 | 21818332b7 |
13 | 106c6371b8 |
14 | 76a567dc7 |
15 | 4494d8d9d |
hex | 2921bf8eb |
11041241323 has 8 divisors (see below), whose sum is σ = 12619214048. Its totient is φ = 9463431744.
The previous prime is 11041241317. The next prime is 11041241357. The reversal of 11041241323 is 32314214011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11041241323 - 25 = 11041241291 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11041241294 and 11041241303.
It is not an unprimeable number, because it can be changed into a prime (11041241303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 195565 + ... + 245617.
It is an arithmetic number, because the mean of its divisors is an integer number (1577401756).
Almost surely, 211041241323 is an apocalyptic number.
11041241323 is a deficient number, since it is larger than the sum of its proper divisors (1577972725).
11041241323 is an equidigital number, since it uses as much as digits as its factorization.
11041241323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81573.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 11041241323 its reverse (32314214011), we get a palindrome (43355455334).
The spelling of 11041241323 in words is "eleven billion, forty-one million, two hundred forty-one thousand, three hundred twenty-three".
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