Base | Representation |
---|---|
bin | 10000000100010010111… |
… | …100011000100001100011 |
3 | 10220112221022212201011201 |
4 | 100010102330120201203 |
5 | 121042221322222201 |
6 | 2203121110022031 |
7 | 142525142445211 |
oct | 20042274304143 |
9 | 3815838781151 |
10 | 1104124414051 |
11 | 3962904a134a |
12 | 159ba1047917 |
13 | 8017040aa69 |
14 | 3b623165cb1 |
15 | 1dac2aee801 |
hex | 10112f18863 |
1104124414051 has 2 divisors, whose sum is σ = 1104124414052. Its totient is φ = 1104124414050.
The previous prime is 1104124414033. The next prime is 1104124414123. The reversal of 1104124414051 is 1504144214011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1104124414051 - 217 = 1104124282979 is a prime.
It is not a weakly prime, because it can be changed into another prime (1104124412051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552062207025 + 552062207026.
It is an arithmetic number, because the mean of its divisors is an integer number (552062207026).
Almost surely, 21104124414051 is an apocalyptic number.
1104124414051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104124414051 is an equidigital number, since it uses as much as digits as its factorization.
1104124414051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2560, while the sum is 28.
Adding to 1104124414051 its reverse (1504144214011), we get a palindrome (2608268628062).
The spelling of 1104124414051 in words is "one trillion, one hundred four billion, one hundred twenty-four million, four hundred fourteen thousand, fifty-one".
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