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11042120131 = 71577445733
BaseRepresentation
bin10100100100010100…
…10110000111000011
31001111112200211012021
422102022112013003
5140103240321011
65023410542311
7540430321030
oct122212260703
931445624167
1011042120131
114756a97319
122181b97997
13106c8841c3
1476a716387
1544960e471
hex2922961c3

11042120131 has 4 divisors (see below), whose sum is σ = 12619565872. Its totient is φ = 9464674392.

The previous prime is 11042120119. The next prime is 11042120171. The reversal of 11042120131 is 13102124011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13102124011 = 53247209887.

It is a cyclic number.

It is not a de Polignac number, because 11042120131 - 29 = 11042119619 is a prime.

It is a super-2 number, since 2×110421201312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11042120171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 788722860 + ... + 788722873.

It is an arithmetic number, because the mean of its divisors is an integer number (3154891468).

Almost surely, 211042120131 is an apocalyptic number.

11042120131 is a deficient number, since it is larger than the sum of its proper divisors (1577445741).

11042120131 is an equidigital number, since it uses as much as digits as its factorization.

11042120131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1577445740.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11042120131 its reverse (13102124011), we get a palindrome (24144244142).

The spelling of 11042120131 in words is "eleven billion, forty-two million, one hundred twenty thousand, one hundred thirty-one".

Divisors: 1 7 1577445733 11042120131