Base | Representation |
---|---|
bin | 1010000010110011010100… |
… | …0100101111111000011011 |
3 | 1110002201120011201011121111 |
4 | 2200230311010233320123 |
5 | 2421413034321331123 |
6 | 35253111042121151 |
7 | 2216564030504566 |
oct | 240546504577033 |
9 | 43081504634544 |
10 | 11043251355163 |
11 | 3578464547235 |
12 | 12a430a6501b7 |
13 | 6214b2c862c1 |
14 | 2a26d38994dd |
15 | 1423d883590d |
hex | a0b3512fe1b |
11043251355163 has 2 divisors, whose sum is σ = 11043251355164. Its totient is φ = 11043251355162.
The previous prime is 11043251355109. The next prime is 11043251355209. The reversal of 11043251355163 is 36155315234011.
11043251355163 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11043251355163 - 221 = 11043249258011 is a prime.
It is not a weakly prime, because it can be changed into another prime (11043251355263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521625677581 + 5521625677582.
It is an arithmetic number, because the mean of its divisors is an integer number (5521625677582).
Almost surely, 211043251355163 is an apocalyptic number.
11043251355163 is a deficient number, since it is larger than the sum of its proper divisors (1).
11043251355163 is an equidigital number, since it uses as much as digits as its factorization.
11043251355163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 40.
Adding to 11043251355163 its reverse (36155315234011), we get a palindrome (47198566589174).
The spelling of 11043251355163 in words is "eleven trillion, forty-three billion, two hundred fifty-one million, three hundred fifty-five thousand, one hundred sixty-three".
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