Base | Representation |
---|---|
bin | 10000000100011111010… |
… | …000011101011001011011 |
3 | 10220120110201121112121011 |
4 | 100010133100131121123 |
5 | 121043132214102413 |
6 | 2203153405554351 |
7 | 142533231435601 |
oct | 20043720353133 |
9 | 3816421545534 |
10 | 1104331003483 |
11 | 396387075014 |
12 | 15a03a2759b7 |
13 | 801a4161426 |
14 | 3b642781871 |
15 | 1dad5d0b33d |
hex | 1011f41d65b |
1104331003483 has 2 divisors, whose sum is σ = 1104331003484. Its totient is φ = 1104331003482.
The previous prime is 1104331003469. The next prime is 1104331003519. The reversal of 1104331003483 is 3843001334011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1104331003483 - 213 = 1104330995291 is a prime.
It is not a weakly prime, because it can be changed into another prime (1104331003423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552165501741 + 552165501742.
It is an arithmetic number, because the mean of its divisors is an integer number (552165501742).
Almost surely, 21104331003483 is an apocalyptic number.
1104331003483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104331003483 is an equidigital number, since it uses as much as digits as its factorization.
1104331003483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 1104331003483 its reverse (3843001334011), we get a palindrome (4947332337494).
The spelling of 1104331003483 in words is "one trillion, one hundred four billion, three hundred thirty-one million, three thousand, four hundred eighty-three".
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