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1104331213129 is a prime number
BaseRepresentation
bin10000000100011111010…
…001010000100101001001
310220120110202000012011211
4100010133101100211021
5121043132242310004
62203153414253121
7142533233301034
oct20043721204511
93816422005154
101104331213129
113963871a8581
1215a03a3571a1
13801a4205991
143b6427d801b
151dad5d4d504
hex1011f450949

1104331213129 has 2 divisors, whose sum is σ = 1104331213130. Its totient is φ = 1104331213128.

The previous prime is 1104331213109. The next prime is 1104331213159. The reversal of 1104331213129 is 9213121334011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 913502027529 + 190829185600 = 955773^2 + 436840^2 .

It is a cyclic number.

It is not a de Polignac number, because 1104331213129 - 27 = 1104331213001 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1104331213129.

It is not a weakly prime, because it can be changed into another prime (1104331213109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552165606564 + 552165606565.

It is an arithmetic number, because the mean of its divisors is an integer number (552165606565).

Almost surely, 21104331213129 is an apocalyptic number.

It is an amenable number.

1104331213129 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104331213129 is an equidigital number, since it uses as much as digits as its factorization.

1104331213129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 1104331213129 in words is "one trillion, one hundred four billion, three hundred thirty-one million, two hundred thirteen thousand, one hundred twenty-nine".