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1104333140113 = 7968271629317
BaseRepresentation
bin10000000100011111011…
…000100111000010010001
310220120110212122002111121
4100010133120213002101
5121043133240440423
62203153523442241
7142533255545050
oct20043730470221
93816425562447
101104333140113
113963882a4325
1215a03ab26381
13801a472bac8
143b642b7a397
151dad60ce45d
hex1011f627091

1104333140113 has 8 divisors (see below), whose sum is σ = 1262108826432. Its totient is φ = 946560906096.

The previous prime is 1104333140069. The next prime is 1104333140129. The reversal of 1104333140113 is 3110413334011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1104333140113 - 217 = 1104333009041 is a prime.

It is a super-3 number, since 3×11043331401133 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1104333140143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 136870 + ... + 1492447.

It is an arithmetic number, because the mean of its divisors is an integer number (157763603304).

Almost surely, 21104333140113 is an apocalyptic number.

It is an amenable number.

1104333140113 is a deficient number, since it is larger than the sum of its proper divisors (157775686319).

1104333140113 is an equidigital number, since it uses as much as digits as its factorization.

1104333140113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1726151.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1104333140113 its reverse (3110413334011), we get a palindrome (4214746474124).

The spelling of 1104333140113 in words is "one trillion, one hundred four billion, three hundred thirty-three million, one hundred forty thousand, one hundred thirteen".

Divisors: 1 7 96827 677789 1629317 11405219 157761877159 1104333140113