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1104333221113 is a prime number
BaseRepresentation
bin10000000100011111011…
…000111010110011111001
310220120110212210012121121
4100010133120322303321
5121043133301033423
62203153525305241
7142533256333153
oct20043730726371
93816425705547
101104333221113
1139638834a171
1215a03ab65221
13801a4759935
143b642b9bad3
151dad60e845d
hex1011f63acf9

1104333221113 has 2 divisors, whose sum is σ = 1104333221114. Its totient is φ = 1104333221112.

The previous prime is 1104333220937. The next prime is 1104333221141. The reversal of 1104333221113 is 3111223334011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 979789164649 + 124544056464 = 989843^2 + 352908^2 .

It is a cyclic number.

It is not a de Polignac number, because 1104333221113 - 213 = 1104333212921 is a prime.

It is not a weakly prime, because it can be changed into another prime (1104333221143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552166610556 + 552166610557.

It is an arithmetic number, because the mean of its divisors is an integer number (552166610557).

Almost surely, 21104333221113 is an apocalyptic number.

It is an amenable number.

1104333221113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104333221113 is an equidigital number, since it uses as much as digits as its factorization.

1104333221113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1104333221113 its reverse (3111223334011), we get a palindrome (4215556555124).

The spelling of 1104333221113 in words is "one trillion, one hundred four billion, three hundred thirty-three million, two hundred twenty-one thousand, one hundred thirteen".