11043343050343 has 16 divisors (see below), whose sum is σ = 11698289562880. Its totient is φ = 10395794695104.

The previous prime is 11043343050247. The next prime is 11043343050361. The reversal of 11043343050343 is 34305034334011.

It is a de Polignac number, because none of the positive numbers 2^k-11043343050343 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11043343050299 and 11043343050308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11043343450343) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14820955 + ... + 15548227.

It is an arithmetic number, because the mean of its divisors is an integer number (731143097680).

Almost surely, 2^{11043343050343} is an apocalyptic number.

11043343050343 is a deficient number, since it is larger than the sum of its proper divisors (654946512537).

11043343050343 is a wasteful number, since it uses less digits than its factorization.

11043343050343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 732358.

The product of its (nonzero) digits is 77760, while the sum is 34.

Adding to 11043343050343 its reverse (34305034334011), we get a palindrome (45348377384354).

The spelling of 11043343050343 in words is "eleven trillion, forty-three billion, three hundred forty-three million, fifty thousand, three hundred forty-three".