Base | Representation |
---|---|
bin | 10100100100011110… |
… | …01111010101111011 |
3 | 1001111122010000010210 |
4 | 22102033033111323 |
5 | 140104102400011 |
6 | 5023454242203 |
7 | 540444243405 |
oct | 122217172573 |
9 | 31448100123 |
10 | 11043403131 |
11 | 4757793252 |
12 | 21824b6363 |
13 | 106cc13187 |
14 | 76a96bb75 |
15 | 4497b46a6 |
hex | 2923cf57b |
11043403131 has 8 divisors (see below), whose sum is σ = 14789404224. Its totient is φ = 7329835400.
The previous prime is 11043403121. The next prime is 11043403139. The reversal of 11043403131 is 13130434011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11043403131 - 29 = 11043402619 is a prime.
It is a super-2 number, since 2×110434031312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11043403098 and 11043403107.
It is not an unprimeable number, because it can be changed into a prime (11043403139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8107545 + ... + 8108906.
It is an arithmetic number, because the mean of its divisors is an integer number (1848675528).
Almost surely, 211043403131 is an apocalyptic number.
11043403131 is a deficient number, since it is larger than the sum of its proper divisors (3746001093).
11043403131 is a wasteful number, since it uses less digits than its factorization.
11043403131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16216681.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 11043403131 its reverse (13130434011), we get a palindrome (24173837142).
The spelling of 11043403131 in words is "eleven billion, forty-three million, four hundred three thousand, one hundred thirty-one".
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