Base | Representation |
---|---|
bin | 10000000100100001111… |
… | …001101011011011101011 |
3 | 10220120120211002020211121 |
4 | 100010201321223123223 |
5 | 121043230043111212 |
6 | 2203202032440111 |
7 | 142534310462536 |
oct | 20044171533353 |
9 | 3816524066747 |
10 | 1104375363307 |
11 | 3963aa113227 |
12 | 15a0510a9037 |
13 | 801b03c3548 |
14 | 3b64860ba1d |
15 | 1dad9b6ed07 |
hex | 10121e6b6eb |
1104375363307 has 2 divisors, whose sum is σ = 1104375363308. Its totient is φ = 1104375363306.
The previous prime is 1104375363263. The next prime is 1104375363319. The reversal of 1104375363307 is 7033635734011.
It is a strong prime.
It is an emirp because it is prime and its reverse (7033635734011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1104375363307 - 219 = 1104374839019 is a prime.
It is not a weakly prime, because it can be changed into another prime (1104375363607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552187681653 + 552187681654.
It is an arithmetic number, because the mean of its divisors is an integer number (552187681654).
Almost surely, 21104375363307 is an apocalyptic number.
1104375363307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104375363307 is an equidigital number, since it uses as much as digits as its factorization.
1104375363307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 476280, while the sum is 43.
The spelling of 1104375363307 in words is "one trillion, one hundred four billion, three hundred seventy-five million, three hundred sixty-three thousand, three hundred seven".
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