Base | Representation |
---|---|
bin | 10000000100100011101… |
… | …000100001101011101001 |
3 | 10220120122211202112222112 |
4 | 100010203220201223221 |
5 | 121043310012440403 |
6 | 2203204551332105 |
7 | 142535112456062 |
oct | 20044350415351 |
9 | 3816584675875 |
10 | 1104404421353 |
11 | 39641455aa42 |
12 | 15a05a981035 |
13 | 801b642885c |
14 | 3b64c413569 |
15 | 1dadc4ae9d8 |
hex | 10123a21ae9 |
1104404421353 has 2 divisors, whose sum is σ = 1104404421354. Its totient is φ = 1104404421352.
The previous prime is 1104404421283. The next prime is 1104404421359. The reversal of 1104404421353 is 3531244044011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 702869287129 + 401535134224 = 838373^2 + 633668^2 .
It is a cyclic number.
It is not a de Polignac number, because 1104404421353 - 232 = 1100109454057 is a prime.
It is not a weakly prime, because it can be changed into another prime (1104404421359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552202210676 + 552202210677.
It is an arithmetic number, because the mean of its divisors is an integer number (552202210677).
Almost surely, 21104404421353 is an apocalyptic number.
It is an amenable number.
1104404421353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104404421353 is an equidigital number, since it uses as much as digits as its factorization.
1104404421353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 1104404421353 its reverse (3531244044011), we get a palindrome (4635648465364).
The spelling of 1104404421353 in words is "one trillion, one hundred four billion, four hundred four million, four hundred twenty-one thousand, three hundred fifty-three".
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