Base | Representation |
---|---|
bin | 1010000010111010010100… |
… | …0111110111110000100011 |
3 | 1110002220102012000022012001 |
4 | 2200232211013313300203 |
5 | 2421430412043101201 |
6 | 35254021354144431 |
7 | 2216661435222223 |
oct | 240564507676043 |
9 | 43086365008161 |
10 | 11045131222051 |
11 | 35792396a1033 |
12 | 12a4754122117 |
13 | 62172258ac84 |
14 | 2a2831402083 |
15 | 1424988b8301 |
hex | a0ba51f7c23 |
11045131222051 has 2 divisors, whose sum is σ = 11045131222052. Its totient is φ = 11045131222050.
The previous prime is 11045131222001. The next prime is 11045131222061. The reversal of 11045131222051 is 15022213154011.
11045131222051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11045131222051 - 27 = 11045131221923 is a prime.
It is not a weakly prime, because it can be changed into another prime (11045131222001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522565611025 + 5522565611026.
It is an arithmetic number, because the mean of its divisors is an integer number (5522565611026).
Almost surely, 211045131222051 is an apocalyptic number.
11045131222051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11045131222051 is an equidigital number, since it uses as much as digits as its factorization.
11045131222051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 11045131222051 its reverse (15022213154011), we get a palindrome (26067344376062).
The spelling of 11045131222051 in words is "eleven trillion, forty-five billion, one hundred thirty-one million, two hundred twenty-two thousand, fifty-one".
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