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11045642135993 is a prime number
BaseRepresentation
bin1010000010111100001110…
…0100110110100110111001
31110002221201210101102100122
42200233003210312212321
52421432433341322433
635254144204543025
72220010211013233
oct240570344664671
943087653342318
1011045642135993
113579481032263
1212a4877251a75
136217a439490a
142a287d1d9253
151424c868a198
hexa0bc39369b9

11045642135993 has 2 divisors, whose sum is σ = 11045642135994. Its totient is φ = 11045642135992.

The previous prime is 11045642135987. The next prime is 11045642136101. The reversal of 11045642135993 is 39953124654011.

11045642135993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7176226607104 + 3869415528889 = 2678848^2 + 1967083^2 .

It is an emirp because it is prime and its reverse (39953124654011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11045642135993 - 220 = 11045641087417 is a prime.

It is not a weakly prime, because it can be changed into another prime (11045642135953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522821067996 + 5522821067997.

It is an arithmetic number, because the mean of its divisors is an integer number (5522821067997).

Almost surely, 211045642135993 is an apocalyptic number.

It is an amenable number.

11045642135993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11045642135993 is an equidigital number, since it uses as much as digits as its factorization.

11045642135993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3499200, while the sum is 53.

The spelling of 11045642135993 in words is "eleven trillion, forty-five billion, six hundred forty-two million, one hundred thirty-five thousand, nine hundred ninety-three".