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110504041 is a prime number
BaseRepresentation
bin1101001011000…
…10100001101001
321200221012001021
412211202201221
5211242112131
614544252441
72511161134
oct645424151
9250835037
10110504041
115741635a
1231011121
1319b8090b
141096721b
159a7be11
hex6962869

110504041 has 2 divisors, whose sum is σ = 110504042. Its totient is φ = 110504040.

The previous prime is 110504033. The next prime is 110504047. The reversal of 110504041 is 140405011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108993600 + 1510441 = 10440^2 + 1229^2 .

It is a cyclic number.

It is not a de Polignac number, because 110504041 - 23 = 110504033 is a prime.

It is a super-2 number, since 2×1105040412 = 24422286154659362, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110504047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55252020 + 55252021.

It is an arithmetic number, because the mean of its divisors is an integer number (55252021).

Almost surely, 2110504041 is an apocalyptic number.

It is an amenable number.

110504041 is a deficient number, since it is larger than the sum of its proper divisors (1).

110504041 is an equidigital number, since it uses as much as digits as its factorization.

110504041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 16.

The square root of 110504041 is about 10512.0902298258. The cubic root of 110504041 is about 479.8727107500.

Adding to 110504041 its reverse (140405011), we get a palindrome (250909052).

The spelling of 110504041 in words is "one hundred ten million, five hundred four thousand, forty-one".