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1105113433 is a prime number
BaseRepresentation
bin100000111011110…
…1011000101011001
32212000110120122011
41001313223011121
54230402112213
6301354225521
736246211024
oct10167530531
92760416564
101105113433
11517898096
1226a1252a1
13147c51298
14a6ab01bb
156704603d
hex41deb159

1105113433 has 2 divisors, whose sum is σ = 1105113434. Its totient is φ = 1105113432.

The previous prime is 1105113421. The next prime is 1105113439. The reversal of 1105113433 is 3343115011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1105097049 + 16384 = 33243^2 + 128^2 .

It is a cyclic number.

It is not a de Polignac number, because 1105113433 - 213 = 1105105241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1105113439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552556716 + 552556717.

It is an arithmetic number, because the mean of its divisors is an integer number (552556717).

Almost surely, 21105113433 is an apocalyptic number.

It is an amenable number.

1105113433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1105113433 is an equidigital number, since it uses as much as digits as its factorization.

1105113433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

The square root of 1105113433 is about 33243.2464269060. The cubic root of 1105113433 is about 1033.8771873062.

Adding to 1105113433 its reverse (3343115011), we get a palindrome (4448228444).

The spelling of 1105113433 in words is "one billion, one hundred five million, one hundred thirteen thousand, four hundred thirty-three".