Base | Representation |
---|---|
bin | 1010000011010010100111… |
… | …0011100100000010101001 |
3 | 1110010112020122110002212012 |
4 | 2200310221303210002221 |
5 | 2422032240433013213 |
6 | 35301020422125305 |
7 | 2220312150014105 |
oct | 240645163440251 |
9 | 43115218402765 |
10 | 11051652235433 |
11 | 3580a85630997 |
12 | 12a5a73b80835 |
13 | 622221588584 |
14 | 2a2c8d4b6905 |
15 | 14272b11a4a8 |
hex | a0d29ce40a9 |
11051652235433 has 2 divisors, whose sum is σ = 11051652235434. Its totient is φ = 11051652235432.
The previous prime is 11051652235373. The next prime is 11051652235511. The reversal of 11051652235433 is 33453225615011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9100858998169 + 1950793237264 = 3016763^2 + 1396708^2 .
It is a cyclic number.
It is not a de Polignac number, because 11051652235433 - 28 = 11051652235177 is a prime.
It is not a weakly prime, because it can be changed into another prime (11051652235133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5525826117716 + 5525826117717.
It is an arithmetic number, because the mean of its divisors is an integer number (5525826117717).
Almost surely, 211051652235433 is an apocalyptic number.
It is an amenable number.
11051652235433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11051652235433 is an equidigital number, since it uses as much as digits as its factorization.
11051652235433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324000, while the sum is 41.
The spelling of 11051652235433 in words is "eleven trillion, fifty-one billion, six hundred fifty-two million, two hundred thirty-five thousand, four hundred thirty-three".
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