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1105311400153 = 56311711676561
BaseRepresentation
bin10000000101011001101…
…100011000000011011001
310220200000001101211222221
4100011121230120003121
5121102134204301103
62203434551144041
7142566434612122
oct20053154300331
93820001354887
101105311400153
1139683a5195a4
1215a272675021
13802cc2c68bc
143b6d6a69049
151db41e191bd
hex10159b180d9

1105311400153 has 8 divisors (see below), whose sum is σ = 1108220894496. Its totient is φ = 1102405262400.

The previous prime is 1105311400121. The next prime is 1105311400183. The reversal of 1105311400153 is 3510041135011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1105311400153 - 25 = 1105311400121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1105311400183) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 179008 + ... + 1497553.

It is an arithmetic number, because the mean of its divisors is an integer number (138527611812).

Almost surely, 21105311400153 is an apocalyptic number.

It is an amenable number.

1105311400153 is a deficient number, since it is larger than the sum of its proper divisors (2909494343).

1105311400153 is a wasteful number, since it uses less digits than its factorization.

1105311400153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1678295.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 1105311400153 its reverse (3510041135011), we get a palindrome (4615352535164).

The spelling of 1105311400153 in words is "one trillion, one hundred five billion, three hundred eleven million, four hundred thousand, one hundred fifty-three".

Divisors: 1 563 1171 659273 1676561 943903843 1963252931 1105311400153