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11054041352017 = 109101413223413
BaseRepresentation
bin1010000011011011100000…
…1101010100011101010001
31110010202102010222210200121
42200312320031110131101
52422102134041231032
635302053445150241
72220425310121426
oct240667015243521
943122363883617
1011054041352017
113581aa118a604
1212a64200bb381
13622512533521
142a3038901d4d
1514281ac41a97
hexa0db8354751

11054041352017 has 4 divisors (see below), whose sum is σ = 11155454575540. Its totient is φ = 10952628128496.

The previous prime is 11054041351981. The next prime is 11054041352059. The reversal of 11054041352017 is 71025314045011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9755902421136 + 1298138930881 = 3123444^2 + 1139359^2 .

It is a cyclic number.

It is not a de Polignac number, because 11054041352017 - 215 = 11054041319249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11054041355017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50706611598 + ... + 50706611815.

It is an arithmetic number, because the mean of its divisors is an integer number (2788863643885).

Almost surely, 211054041352017 is an apocalyptic number.

It is an amenable number.

11054041352017 is a deficient number, since it is larger than the sum of its proper divisors (101413223523).

11054041352017 is a wasteful number, since it uses less digits than its factorization.

11054041352017 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 101413223522.

The product of its (nonzero) digits is 16800, while the sum is 34.

Adding to 11054041352017 its reverse (71025314045011), we get a palindrome (82079355397028).

The spelling of 11054041352017 in words is "eleven trillion, fifty-four billion, forty-one million, three hundred fifty-two thousand, seventeen".

Divisors: 1 109 101413223413 11054041352017