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1105501512114 = 23261416750673
BaseRepresentation
bin10000000101100101000…
…001100110000110110010
310220200111022010112120200
4100011211001212012302
5121103031341341424
62203505502020030
7142604233544316
oct20054501460662
93820438115520
101105501512114
1139692786851a
1215a306277616
138032c7cb29c
143b713dd5b46
151db5396d8c9
hex101650661b2

1105501512114 has 12 divisors (see below), whose sum is σ = 2395253276286. Its totient is φ = 368500504032.

The previous prime is 1105501512103. The next prime is 1105501512161. The reversal of 1105501512114 is 4112151055011.

1105501512114 is a `hidden beast` number, since 1 + 105 + 501 + 51 + 2 + 1 + 1 + 4 = 666.

It can be written as a sum of positive squares in only one way, i.e., 1027678925025 + 77822587089 = 1013745^2 + 278967^2 .

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 30708375319 + ... + 30708375354.

Almost surely, 21105501512114 is an apocalyptic number.

1105501512114 is an abundant number, since it is smaller than the sum of its proper divisors (1289751764172).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1105501512114 is a wasteful number, since it uses less digits than its factorization.

1105501512114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61416750681 (or 61416750678 counting only the distinct ones).

The product of its (nonzero) digits is 1000, while the sum is 27.

Adding to 1105501512114 its reverse (4112151055011), we get a palindrome (5217652567125).

The spelling of 1105501512114 in words is "one trillion, one hundred five billion, five hundred one million, five hundred twelve thousand, one hundred fourteen".

Divisors: 1 2 3 6 9 18 61416750673 122833501346 184250252019 368500504038 552750756057 1105501512114