Base | Representation |
---|---|
bin | 10000000110001000110… |
… | …110010011000100000011 |
3 | 10220202001012001102112202 |
4 | 100012020312103010003 |
5 | 121110244221432212 |
6 | 2204045251543415 |
7 | 142625152244045 |
oct | 20061066230403 |
9 | 3822035042482 |
10 | 1106102530307 |
11 | 397106051375 |
12 | 15a4535bab6b |
13 | 803c7192458 |
14 | 3b76db65a95 |
15 | 1db8b5dd0c2 |
hex | 10188d93103 |
1106102530307 has 2 divisors, whose sum is σ = 1106102530308. Its totient is φ = 1106102530306.
The previous prime is 1106102530277. The next prime is 1106102530399. The reversal of 1106102530307 is 7030352016011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1106102530307 - 232 = 1101807563011 is a prime.
It is a super-3 number, since 3×11061025303073 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1106102530307.
It is not a weakly prime, because it can be changed into another prime (1106102530007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 553051265153 + 553051265154.
It is an arithmetic number, because the mean of its divisors is an integer number (553051265154).
Almost surely, 21106102530307 is an apocalyptic number.
1106102530307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1106102530307 is an equidigital number, since it uses as much as digits as its factorization.
1106102530307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3780, while the sum is 29.
Adding to 1106102530307 its reverse (7030352016011), we get a palindrome (8136454546318).
The spelling of 1106102530307 in words is "one trillion, one hundred six billion, one hundred two million, five hundred thirty thousand, three hundred seven".
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