Base | Representation |
---|---|
bin | 10000000110100001001… |
… | …110000110011111010111 |
3 | 10220210002200110100111010 |
4 | 100012201032012133113 |
5 | 121112113411022242 |
6 | 2204154015543303 |
7 | 142641245625243 |
oct | 20064116063727 |
9 | 3823080410433 |
10 | 1106511423447 |
11 | 3972a5940891 |
12 | 15a54852ab33 |
13 | 80460ac8861 |
14 | 3b7ac1a3423 |
15 | 1dbb245b89c |
hex | 101a13867d7 |
1106511423447 has 16 divisors (see below), whose sum is σ = 1492085802240. Its totient is φ = 729307444800.
The previous prime is 1106511423427. The next prime is 1106511423461. The reversal of 1106511423447 is 7443241156011.
It is not a de Polignac number, because 1106511423447 - 28 = 1106511423191 is a prime.
It is a super-2 number, since 2×11065114234472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1106511423427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2321572 + ... + 2757302.
It is an arithmetic number, because the mean of its divisors is an integer number (93255362640).
Almost surely, 21106511423447 is an apocalyptic number.
1106511423447 is a deficient number, since it is larger than the sum of its proper divisors (385574378793).
1106511423447 is an equidigital number, since it uses as much as digits as its factorization.
1106511423447 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 445334.
The product of its (nonzero) digits is 80640, while the sum is 39.
Adding to 1106511423447 its reverse (7443241156011), we get a palindrome (8549752579458).
The spelling of 1106511423447 in words is "one trillion, one hundred six billion, five hundred eleven million, four hundred twenty-three thousand, four hundred forty-seven".
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