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11074150752017 is a prime number
BaseRepresentation
bin1010000100100110011011…
…0100100101111100010001
31110012200022121101011112012
42201021212310211330101
52422414330043031032
635315221123312305
72222036531160653
oct241114664457421
943180277334465
1011074150752017
11358a580440451
1212aa2b281b695
13624398793392
142a3dc55446d3
151430e63bc6b2
hexa1266d25f11

11074150752017 has 2 divisors, whose sum is σ = 11074150752018. Its totient is φ = 11074150752016.

The previous prime is 11074150751999. The next prime is 11074150752073. The reversal of 11074150752017 is 71025705147011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10193773887361 + 880376864656 = 3192769^2 + 938284^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11074150752017 is a prime.

It is not a weakly prime, because it can be changed into another prime (11074150752817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5537075376008 + 5537075376009.

It is an arithmetic number, because the mean of its divisors is an integer number (5537075376009).

Almost surely, 211074150752017 is an apocalyptic number.

It is an amenable number.

11074150752017 is a deficient number, since it is larger than the sum of its proper divisors (1).

11074150752017 is an equidigital number, since it uses as much as digits as its factorization.

11074150752017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 68600, while the sum is 41.

Adding to 11074150752017 its reverse (71025705147011), we get a palindrome (82099855899028).

The spelling of 11074150752017 in words is "eleven trillion, seventy-four billion, one hundred fifty million, seven hundred fifty-two thousand, seventeen".