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11076749150521 is a prime number
BaseRepresentation
bin1010000100110000000110…
…1100101100100100111001
31110012221000200201111011211
42201030001230230210321
52422440140240304041
635320331024123121
72222161112201545
oct241140154544471
943187020644154
1011076749150521
11359069414172a
1212aa8b8a664a1
136246c0bc53a2
142a419068aa25
151431e9583481
hexa1301b2c939

11076749150521 has 2 divisors, whose sum is σ = 11076749150522. Its totient is φ = 11076749150520.

The previous prime is 11076749150513. The next prime is 11076749150591. The reversal of 11076749150521 is 12505194767011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10521336682921 + 555412467600 = 3243661^2 + 745260^2 .

It is a cyclic number.

It is not a de Polignac number, because 11076749150521 - 23 = 11076749150513 is a prime.

It is a super-3 number, since 3×110767491505213 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (11076749150591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5538374575260 + 5538374575261.

It is an arithmetic number, because the mean of its divisors is an integer number (5538374575261).

Almost surely, 211076749150521 is an apocalyptic number.

It is an amenable number.

11076749150521 is a deficient number, since it is larger than the sum of its proper divisors (1).

11076749150521 is an equidigital number, since it uses as much as digits as its factorization.

11076749150521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 529200, while the sum is 49.

The spelling of 11076749150521 in words is "eleven trillion, seventy-six billion, seven hundred forty-nine million, one hundred fifty thousand, five hundred twenty-one".