110894098353 has 4 divisors (see below), whose sum is σ = 147858797808. Its totient is φ = 73929398900.

The previous prime is 110894098313. The next prime is 110894098361. The reversal of 110894098353 is 353890498011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110894098353 - 2⁹ = 110894097841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110894098296 and 110894098305.

It is not an unprimeable number, because it can be changed into a prime (110894098303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18482349723 + ... + 18482349728.

It is an arithmetic number, because the mean of its divisors is an integer number (36964699452).

Almost surely, 2^110894098353 is an apocalyptic number.

It is an amenable number.

110894098353 is a deficient number, since it is larger than the sum of its proper divisors (36964699455).

110894098353 is an equidigital number, since it uses as much as digits as its factorization.

110894098353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36964699454.

The product of its (nonzero) digits is 933120, while the sum is 51.

The spelling of 110894098353 in words is "one hundred ten billion, eight hundred ninety-four million, ninety-eight thousand, three hundred fifty-three".