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11095641172657 is a prime number
BaseRepresentation
bin1010000101110110011111…
…0000000010101010110001
31110021201210022101122112101
42201131213300002222301
52423242333120011112
635333133413500401
72223430221554356
oct241354760025261
943251708348471
1011095641172657
1135986a91a7568
1212b24ab941701
13626411b88002
142a506375862d
15143952dde757
hexa1767c02ab1

11095641172657 has 2 divisors, whose sum is σ = 11095641172658. Its totient is φ = 11095641172656.

The previous prime is 11095641172639. The next prime is 11095641172687. The reversal of 11095641172657 is 75627114659011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10843164066816 + 252477105841 = 3292896^2 + 502471^2 .

It is a cyclic number.

It is not a de Polignac number, because 11095641172657 - 215 = 11095641139889 is a prime.

It is a super-2 number, since 2×110956411726572 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11095641172598 and 11095641172607.

It is not a weakly prime, because it can be changed into another prime (11095641172687) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5547820586328 + 5547820586329.

It is an arithmetic number, because the mean of its divisors is an integer number (5547820586329).

Almost surely, 211095641172657 is an apocalyptic number.

It is an amenable number.

11095641172657 is a deficient number, since it is larger than the sum of its proper divisors (1).

11095641172657 is an equidigital number, since it uses as much as digits as its factorization.

11095641172657 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3175200, while the sum is 55.

The spelling of 11095641172657 in words is "eleven trillion, ninety-five billion, six hundred forty-one million, one hundred seventy-two thousand, six hundred fifty-seven".