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11100000011153 is a prime number
BaseRepresentation
bin1010000110000110101110…
…0011101100001110010001
31110022011001002022120212012
42201201223203230032101
52423330300000324103
635335134122512305
72223643230226334
oct241415343541621
943264032276765
1011100000011153
11359a5356a2429
1212b3307665695
13626957c388a1
142a53585da61b
15143b0a8e72d8
hexa186b8ec391

11100000011153 has 2 divisors, whose sum is σ = 11100000011154. Its totient is φ = 11100000011152.

The previous prime is 11100000011099. The next prime is 11100000011173. The reversal of 11100000011153 is 35111000000111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9104654481664 + 1995345529489 = 3017392^2 + 1412567^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11100000011153 is a prime.

It is not a weakly prime, because it can be changed into another prime (11100000011173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550000005576 + 5550000005577.

It is an arithmetic number, because the mean of its divisors is an integer number (5550000005577).

Almost surely, 211100000011153 is an apocalyptic number.

It is an amenable number.

11100000011153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100000011153 is an equidigital number, since it uses as much as digits as its factorization.

11100000011153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 14.

Adding to 11100000011153 its reverse (35111000000111), we get a palindrome (46211000011264).

The spelling of 11100000011153 in words is "eleven trillion, one hundred billion, eleven thousand, one hundred fifty-three".