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1110000133131 = 3370000044377
BaseRepresentation
bin10000001001110001001…
…010011110010000001011
310221010002211002011110220
4100021301022132100023
5121141240013230011
62205532123041123
7143123560312431
oct20116112362013
93833084064426
101110000133131
1139882615702a
1215b1609701a3
1380898811206
143ba1d662d51
151dd18888506
hex1027129e40b

1110000133131 has 4 divisors (see below), whose sum is σ = 1480000177512. Its totient is φ = 740000088752.

The previous prime is 1110000133013. The next prime is 1110000133153. The reversal of 1110000133131 is 1313310000111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1110000133131 - 27 = 1110000133003 is a prime.

It is a super-2 number, since 2×11100001331312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1110000133131.

It is not an unprimeable number, because it can be changed into a prime (1110000133181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185000022186 + ... + 185000022191.

It is an arithmetic number, because the mean of its divisors is an integer number (370000044378).

Almost surely, 21110000133131 is an apocalyptic number.

1110000133131 is a deficient number, since it is larger than the sum of its proper divisors (370000044381).

1110000133131 is an equidigital number, since it uses as much as digits as its factorization.

1110000133131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 370000044380.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 1110000133131 its reverse (1313310000111), we get a palindrome (2423310133242).

The spelling of 1110000133131 in words is "one trillion, one hundred ten billion, one hundred thirty-three thousand, one hundred thirty-one".

Divisors: 1 3 370000044377 1110000133131