Base | Representation |
---|---|
bin | 1010000110000110110000… |
… | …1101100111000100010011 |
3 | 1110022011001211222212211121 |
4 | 2201201230031213010103 |
5 | 2423330310304000313 |
6 | 35335135154223111 |
7 | 2223643422515125 |
oct | 241415415470423 |
9 | 43264054885747 |
10 | 11100011000083 |
11 | 359a540918595 |
12 | 12b330b284a97 |
13 | 62695a2b5605 |
14 | 2a5359c5b215 |
15 | 143b0b86828d |
hex | a186c367113 |
11100011000083 has 2 divisors, whose sum is σ = 11100011000084. Its totient is φ = 11100011000082.
The previous prime is 11100011000053. The next prime is 11100011000107. The reversal of 11100011000083 is 38000011000111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11100011000083 is a prime.
It is not a weakly prime, because it can be changed into another prime (11100011000053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550005500041 + 5550005500042.
It is an arithmetic number, because the mean of its divisors is an integer number (5550005500042).
Almost surely, 211100011000083 is an apocalyptic number.
11100011000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100011000083 is an equidigital number, since it uses as much as digits as its factorization.
11100011000083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 11100011000083 its reverse (38000011000111), we get a palindrome (49100022000194).
The spelling of 11100011000083 in words is "eleven trillion, one hundred billion, eleven million, eighty-three", and thus it is an aban number.
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