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111001000113 = 32311367291041
BaseRepresentation
bin110011101100000101…
…1001101100010110001
3101121111211222001101100
41213120023031202301
53304312224000423
6122554304355013
711006464635063
oct1473013154261
9347454861340
10111001000113
1143091197333
121961a015a69
13a60c9c7373
145530111733
152d49e25343
hex19d82cd8b1

111001000113 has 24 divisors (see below), whose sum is σ = 165628509696. Its totient is φ = 71560915200.

The previous prime is 111001000069. The next prime is 111001000127. The reversal of 111001000113 is 311000100111.

It is not a de Polignac number, because 111001000113 - 210 = 111000999089 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a junction number, because it is equal to n+sod(n) for n = 111001000095 and 111001000104.

It is not an unprimeable number, because it can be changed into a prime (111001000133) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 235873 + ... + 526913.

It is an arithmetic number, because the mean of its divisors is an integer number (6901187904).

Almost surely, 2111001000113 is an apocalyptic number.

It is an amenable number.

111001000113 is a deficient number, since it is larger than the sum of its proper divisors (54627509583).

111001000113 is a wasteful number, since it uses less digits than its factorization.

111001000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 292445 (or 292442 counting only the distinct ones).

The product of its (nonzero) digits is 3, while the sum is 9.

Adding to 111001000113 its reverse (311000100111), we get a palindrome (422001100224).

The spelling of 111001000113 in words is "one hundred eleven billion, one million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 3 9 31 93 279 1367 4101 12303 42377 127131 291041 381393 873123 2619369 9022271 27066813 81200439 397853047 1193559141 3580677423 12333444457 37000333371 111001000113