Base | Representation |
---|---|
bin | 10000001001110001110… |
… | …000100010000001000001 |
3 | 10221010010111212001012012 |
4 | 100021301300202001001 |
5 | 121141300042010032 |
6 | 2205533120542305 |
7 | 143124041154524 |
oct | 20116160420101 |
9 | 3833114761165 |
10 | 1110010110017 |
11 | 398830850896 |
12 | 15b164181995 |
13 | 8089a8c53b3 |
14 | 3ba20adcbbb |
15 | 1dd196a96b2 |
hex | 10271c22041 |
1110010110017 has 2 divisors, whose sum is σ = 1110010110018. Its totient is φ = 1110010110016.
The previous prime is 1110010109987. The next prime is 1110010110023. The reversal of 1110010110017 is 7100110100111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 961662654736 + 148347455281 = 980644^2 + 385159^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1110010110017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1110010109983 and 1110010110010.
It is not a weakly prime, because it can be changed into another prime (1110010110037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555005055008 + 555005055009.
It is an arithmetic number, because the mean of its divisors is an integer number (555005055009).
Almost surely, 21110010110017 is an apocalyptic number.
It is an amenable number.
1110010110017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110010110017 is an equidigital number, since it uses as much as digits as its factorization.
1110010110017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7, while the sum is 14.
Adding to 1110010110017 its reverse (7100110100111), we get a palindrome (8210120210128).
The spelling of 1110010110017 in words is "one trillion, one hundred ten billion, ten million, one hundred ten thousand, seventeen".
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