111001200000121 has 4 divisors (see below), whose sum is σ = 116843368421200. Its totient is φ = 105159031579044.

The previous prime is 111001200000113. The next prime is 111001200000139. The reversal of 111001200000121 is 121000002100111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111001200000121 - 2³ = 111001200000113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111001200000098 and 111001200000107.

It is not an unprimeable number, because it can be changed into a prime (111001200000181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2921084210511 + ... + 2921084210548.

It is an arithmetic number, because the mean of its divisors is an integer number (29210842105300).

Almost surely, 2^{111001200000121} is an apocalyptic number.

It is an amenable number.

111001200000121 is a deficient number, since it is larger than the sum of its proper divisors (5842168421079).

111001200000121 is an equidigital number, since it uses as much as digits as its factorization.

111001200000121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5842168421078.

The product of its (nonzero) digits is 4, while the sum is 10.

Adding to 111001200000121 its reverse (121000002100111), we get a palindrome (232001202100232).

The spelling of 111001200000121 in words is "one hundred eleven trillion, one billion, two hundred million, one hundred twenty-one", and thus it is an aban number.