Base | Representation |
---|---|
bin | 10000001001110001111… |
… | …000001100101110101001 |
3 | 10221010010122122011100011 |
4 | 100021301320030232221 |
5 | 121141301100314402 |
6 | 2205533232011521 |
7 | 143124064225465 |
oct | 20116170145651 |
9 | 3833118564304 |
10 | 1110012119977 |
11 | 3988319a3a12 |
12 | 15b164990ba1 |
13 | 8089b14a217 |
14 | 3ba210a34a5 |
15 | 1dd19954ed7 |
hex | 10271e0cba9 |
1110012119977 has 2 divisors, whose sum is σ = 1110012119978. Its totient is φ = 1110012119976.
The previous prime is 1110012119969. The next prime is 1110012119999. The reversal of 1110012119977 is 7799112100111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 599317512336 + 510694607641 = 774156^2 + 714629^2 .
It is an emirp because it is prime and its reverse (7799112100111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1110012119977 - 23 = 1110012119969 is a prime.
It is not a weakly prime, because it can be changed into another prime (1110012114977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555006059988 + 555006059989.
It is an arithmetic number, because the mean of its divisors is an integer number (555006059989).
Almost surely, 21110012119977 is an apocalyptic number.
It is an amenable number.
1110012119977 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110012119977 is an equidigital number, since it uses as much as digits as its factorization.
1110012119977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7938, while the sum is 40.
The spelling of 1110012119977 in words is "one trillion, one hundred ten billion, twelve million, one hundred nineteen thousand, nine hundred seventy-seven".
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