1110013034203 has 2 divisors, whose sum is σ = 1110013034204. Its totient is φ = 1110013034202.

The previous prime is 1110013034197. The next prime is 1110013034227. The reversal of 1110013034203 is 3024303100111.

It is a weak prime.

It is an emirp because it is prime and its reverse (3024303100111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1110013034203 - 2²⁵ = 1109979479771 is a prime.

It is a super-3 number, since 3×1110013034203³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1110013031203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555006517101 + 555006517102.

It is an arithmetic number, because the mean of its divisors is an integer number (555006517102).

Almost surely, 2^{1110013034203} is an apocalyptic number.

1110013034203 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110013034203 is an equidigital number, since it uses as much as digits as its factorization.

1110013034203 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1110013034203 its reverse (3024303100111), we get a palindrome (4134316134314).

The spelling of 1110013034203 in words is "one trillion, one hundred ten billion, thirteen million, thirty-four thousand, two hundred three".