Search a number
-
+
1110022000147 is a prime number
BaseRepresentation
bin10000001001110010011…
…101111000111000010011
310221010011100020010101101
4100021302131320320103
5121141311113001042
62205534223445231
7143124244215604
oct20116235707023
93833140203341
101110022000147
11398837532045
1215b168156817
13808a01c9388
143ba22515dab
151dd1a7576b7
hex10272778e13

1110022000147 has 2 divisors, whose sum is σ = 1110022000148. Its totient is φ = 1110022000146.

The previous prime is 1110022000121. The next prime is 1110022000151. The reversal of 1110022000147 is 7410002200111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1110022000147 is a prime.

It is not a weakly prime, because it can be changed into another prime (1110022000177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555011000073 + 555011000074.

It is an arithmetic number, because the mean of its divisors is an integer number (555011000074).

Almost surely, 21110022000147 is an apocalyptic number.

1110022000147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110022000147 is an equidigital number, since it uses as much as digits as its factorization.

1110022000147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 19.

Adding to 1110022000147 its reverse (7410002200111), we get a palindrome (8520024200258).

The spelling of 1110022000147 in words is "one trillion, one hundred ten billion, twenty-two million, one hundred forty-seven", and thus it is an aban number.