Base | Representation |
---|---|
bin | 1010000110000111100011… |
… | …0010100011011101101011 |
3 | 1110022011121120001100201202 |
4 | 2201201320302203131223 |
5 | 2423331223313324433 |
6 | 35335212133034415 |
7 | 2223651564213041 |
oct | 241417062433553 |
9 | 43264546040652 |
10 | 11100222011243 |
11 | 359a639a41382 |
12 | 12b3369a85a0b |
13 | 626991c267a1 |
14 | 2a5379ca8391 |
15 | 143b20149ee8 |
hex | a1878ca376b |
11100222011243 has 2 divisors, whose sum is σ = 11100222011244. Its totient is φ = 11100222011242.
The previous prime is 11100222011189. The next prime is 11100222011339. The reversal of 11100222011243 is 34211022200111.
11100222011243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11100222011243 is a prime.
It is not a weakly prime, because it can be changed into another prime (11100222011443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550111005621 + 5550111005622.
It is an arithmetic number, because the mean of its divisors is an integer number (5550111005622).
Almost surely, 211100222011243 is an apocalyptic number.
11100222011243 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100222011243 is an equidigital number, since it uses as much as digits as its factorization.
11100222011243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 11100222011243 its reverse (34211022200111), we get a palindrome (45311244211354).
The spelling of 11100222011243 in words is "eleven trillion, one hundred billion, two hundred twenty-two million, eleven thousand, two hundred forty-three".
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