Base | Representation |
---|---|
bin | 110011101100000111… |
… | …1111001110101101001 |
3 | 101121111221021112122012 |
4 | 1213120033321311221 |
5 | 3304313032330441 |
6 | 122554351005305 |
7 | 11006511250106 |
oct | 1473017716551 |
9 | 347457245565 |
10 | 111002230121 |
11 | 43091957472 |
12 | 1961a509835 |
13 | a610038193 |
14 | 5530351aad |
15 | 2d4a0b99eb |
hex | 19d83f9d69 |
111002230121 has 4 divisors (see below), whose sum is σ = 111007344000. Its totient is φ = 110997116244.
The previous prime is 111002230117. The next prime is 111002230123. The reversal of 111002230121 is 121032200111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 111002230121 - 22 = 111002230117 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 111002230096 and 111002230105.
It is not an unprimeable number, because it can be changed into a prime (111002230123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2524241 + ... + 2567838.
It is an arithmetic number, because the mean of its divisors is an integer number (27751836000).
Almost surely, 2111002230121 is an apocalyptic number.
It is an amenable number.
111002230121 is a deficient number, since it is larger than the sum of its proper divisors (5113879).
111002230121 is an equidigital number, since it uses as much as digits as its factorization.
111002230121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5113878.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 111002230121 its reverse (121032200111), we get a palindrome (232034430232).
The spelling of 111002230121 in words is "one hundred eleven billion, two million, two hundred thirty thousand, one hundred twenty-one".
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