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11100431113 = 31358078423
BaseRepresentation
bin10100101011010001…
…10010001100001001
31001122121102022211021
422111220302030021
5140213202243423
65033252432441
7542036051632
oct122550621411
931577368737
1011100431113
1147869a4212
122199618721
13107b98c445
14774374889
1544e7cb95d
hex295a32309

11100431113 has 4 divisors (see below), whose sum is σ = 11458509568. Its totient is φ = 10742352660.

The previous prime is 11100431107. The next prime is 11100431119. The reversal of 11100431113 is 31113400111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (11100431107) and next prime (11100431119).

It is a cyclic number.

It is not a de Polignac number, because 11100431113 - 25 = 11100431081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11100431119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 179039181 + ... + 179039242.

It is an arithmetic number, because the mean of its divisors is an integer number (2864627392).

Almost surely, 211100431113 is an apocalyptic number.

It is an amenable number.

11100431113 is a deficient number, since it is larger than the sum of its proper divisors (358078455).

11100431113 is an equidigital number, since it uses as much as digits as its factorization.

11100431113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 358078454.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 11100431113 its reverse (31113400111), we get a palindrome (42213831224).

The spelling of 11100431113 in words is "eleven billion, one hundred million, four hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 31 358078423 11100431113