Search a number
-
+
1110043300411 = 5851189718561
BaseRepresentation
bin10000001001110011101…
…111001001001000111011
310221010012211022021212001
4100021303233021020323
5121141332041103121
62205540304201431
7143124623241523
oct20116357111073
93833184267761
101110043300411
11398848560271
1215b173309277
13808a4746596
143ba2529c683
151dd1c563991
hex10273bc923b

1110043300411 has 4 divisors (see below), whose sum is σ = 1110233024824. Its totient is φ = 1109853576000.

The previous prime is 1110043300391. The next prime is 1110043300433. The reversal of 1110043300411 is 1140033400111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1110043300411 - 27 = 1110043300283 is a prime.

It is a super-2 number, since 2×11100433004112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1110043300441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94853430 + ... + 94865131.

It is an arithmetic number, because the mean of its divisors is an integer number (277558256206).

Almost surely, 21110043300411 is an apocalyptic number.

1110043300411 is a deficient number, since it is larger than the sum of its proper divisors (189724413).

1110043300411 is an equidigital number, since it uses as much as digits as its factorization.

1110043300411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 189724412.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1110043300411 its reverse (1140033400111), we get a palindrome (2250076700522).

The spelling of 1110043300411 in words is "one trillion, one hundred ten billion, forty-three million, three hundred thousand, four hundred eleven".

Divisors: 1 5851 189718561 1110043300411