Base | Representation |
---|---|
bin | 10000001001110011101… |
… | …111001001001000111011 |
3 | 10221010012211022021212001 |
4 | 100021303233021020323 |
5 | 121141332041103121 |
6 | 2205540304201431 |
7 | 143124623241523 |
oct | 20116357111073 |
9 | 3833184267761 |
10 | 1110043300411 |
11 | 398848560271 |
12 | 15b173309277 |
13 | 808a4746596 |
14 | 3ba2529c683 |
15 | 1dd1c563991 |
hex | 10273bc923b |
1110043300411 has 4 divisors (see below), whose sum is σ = 1110233024824. Its totient is φ = 1109853576000.
The previous prime is 1110043300391. The next prime is 1110043300433. The reversal of 1110043300411 is 1140033400111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1110043300411 - 27 = 1110043300283 is a prime.
It is a super-2 number, since 2×11100433004112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1110043300441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94853430 + ... + 94865131.
It is an arithmetic number, because the mean of its divisors is an integer number (277558256206).
Almost surely, 21110043300411 is an apocalyptic number.
1110043300411 is a deficient number, since it is larger than the sum of its proper divisors (189724413).
1110043300411 is an equidigital number, since it uses as much as digits as its factorization.
1110043300411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 189724412.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1110043300411 its reverse (1140033400111), we get a palindrome (2250076700522).
The spelling of 1110043300411 in words is "one trillion, one hundred ten billion, forty-three million, three hundred thousand, four hundred eleven".
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