Base | Representation |
---|---|
bin | 10100101011010001… |
… | …10010111110001001 |
3 | 1001122121102111012210 |
4 | 22111220302332021 |
5 | 140213202344223 |
6 | 5033252455333 |
7 | 542036064153 |
oct | 122550627611 |
9 | 31577374183 |
10 | 11100434313 |
11 | 47869a6661 |
12 | 219961a549 |
13 | 107b990a37 |
14 | 774375ad3 |
15 | 44e7cc893 |
hex | 295a32f89 |
11100434313 has 16 divisors (see below), whose sum is σ = 15561950400. Its totient is φ = 7027970880.
The previous prime is 11100434311. The next prime is 11100434329. The reversal of 11100434313 is 31343400111.
11100434313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11100434313 - 21 = 11100434311 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11100434313.
It is not an unprimeable number, because it can be changed into a prime (11100434311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1040523 + ... + 1051136.
It is an arithmetic number, because the mean of its divisors is an integer number (972621900).
Almost surely, 211100434313 is an apocalyptic number.
It is an amenable number.
11100434313 is a deficient number, since it is larger than the sum of its proper divisors (4461516087).
11100434313 is a wasteful number, since it uses less digits than its factorization.
11100434313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2091752.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 11100434313 its reverse (31343400111), we get a palindrome (42443834424).
The spelling of 11100434313 in words is "eleven billion, one hundred million, four hundred thirty-four thousand, three hundred thirteen".
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