Base | Representation |
---|---|
bin | 10000001001110100001… |
… | …000101111010110111011 |
3 | 10221010020021221012102220 |
4 | 100021310020233112323 |
5 | 121141340300314210 |
6 | 2205541104055123 |
7 | 143125034256603 |
oct | 20116410572673 |
9 | 3833207835386 |
10 | 1110050010555 |
11 | 398851323742 |
12 | 15b1756044a3 |
13 | 808a5c55895 |
14 | 3ba26127c03 |
15 | 1dd1ce3bc70 |
hex | 1027422f5bb |
1110050010555 has 16 divisors (see below), whose sum is σ = 1776236182560. Its totient is φ = 591974617088.
The previous prime is 1110050010547. The next prime is 1110050010613. The reversal of 1110050010555 is 5550100500111.
It is a cyclic number.
It is not a de Polignac number, because 1110050010555 - 23 = 1110050010547 is a prime.
It is a super-2 number, since 2×11100500105552 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3076860 + ... + 3418649.
It is an arithmetic number, because the mean of its divisors is an integer number (111014761410).
Almost surely, 21110050010555 is an apocalyptic number.
1110050010555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1110050010555 is a deficient number, since it is larger than the sum of its proper divisors (666186172005).
1110050010555 is a wasteful number, since it uses less digits than its factorization.
1110050010555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6506910.
The product of its (nonzero) digits is 625, while the sum is 24.
Adding to 1110050010555 its reverse (5550100500111), we get a palindrome (6660150510666).
The spelling of 1110050010555 in words is "one trillion, one hundred ten billion, fifty million, ten thousand, five hundred fifty-five".
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