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11100628649153 is a prime number
BaseRepresentation
bin1010000110001001000100…
…0001110000010011000001
31110022012122220012201002002
42201202101001300103001
52423333041413233103
635335320340433345
72223664632452231
oct241422101602301
943265586181062
1011100628649153
11359a82853046a
1212b34620a8855
13626a28250534
142a53b7cb9cc1
15143b45bc0488
hexa18910704c1

11100628649153 has 2 divisors, whose sum is σ = 11100628649154. Its totient is φ = 11100628649152.

The previous prime is 11100628649141. The next prime is 11100628649167. The reversal of 11100628649153 is 35194682600111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7167276689329 + 3933351959824 = 2677177^2 + 1983268^2 .

It is a cyclic number.

It is not a de Polignac number, because 11100628649153 - 210 = 11100628648129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11100628649098 and 11100628649107.

It is not a weakly prime, because it can be changed into another prime (11100628649183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550314324576 + 5550314324577.

It is an arithmetic number, because the mean of its divisors is an integer number (5550314324577).

Almost surely, 211100628649153 is an apocalyptic number.

It is an amenable number.

11100628649153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100628649153 is an equidigital number, since it uses as much as digits as its factorization.

11100628649153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 47.

The spelling of 11100628649153 in words is "eleven trillion, one hundred billion, six hundred twenty-eight million, six hundred forty-nine thousand, one hundred fifty-three".