Base | Representation |
---|---|
bin | 11001001111011010001001… |
… | …011101110101010000100011 |
3 | 112120001110021221010101201001 |
4 | 121033122021131311100203 |
5 | 104022242020421000311 |
6 | 1032033145414052431 |
7 | 32245132024603105 |
oct | 3117321135652043 |
9 | 476043257111631 |
10 | 111010031031331 |
11 | 3240a0a9545423 |
12 | 1054a5a294a117 |
13 | 49c327c8009a3 |
14 | 1d5acb26a7575 |
15 | cc795b9164c1 |
hex | 64f689775423 |
111010031031331 has 2 divisors, whose sum is σ = 111010031031332. Its totient is φ = 111010031031330.
The previous prime is 111010031031281. The next prime is 111010031031397. The reversal of 111010031031331 is 133130130010111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111010031031331 - 27 = 111010031031203 is a prime.
It is a super-2 number, since 2×1110100310313312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111010031031299 and 111010031031308.
It is not a weakly prime, because it can be changed into another prime (111010091031331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55505015515665 + 55505015515666.
It is an arithmetic number, because the mean of its divisors is an integer number (55505015515666).
Almost surely, 2111010031031331 is an apocalyptic number.
111010031031331 is a deficient number, since it is larger than the sum of its proper divisors (1).
111010031031331 is an equidigital number, since it uses as much as digits as its factorization.
111010031031331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 111010031031331 its reverse (133130130010111), we get a palindrome (244140161041442).
The spelling of 111010031031331 in words is "one hundred eleven trillion, ten billion, thirty-one million, thirty-one thousand, three hundred thirty-one".
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