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1110100555001 is a prime number
BaseRepresentation
bin10000001001110111001…
…001100011010011111001
310221010100211001010101102
4100021313021203103321
5121141441220230001
62205550111301145
7143126220012524
oct20116711432371
93833324033342
101110100555001
11398877906509
1215b18a51a7b5
13808b3571a39
143ba2cb23bbb
151dd225c2e6b
hex102772634f9

1110100555001 has 2 divisors, whose sum is σ = 1110100555002. Its totient is φ = 1110100555000.

The previous prime is 1110100554991. The next prime is 1110100555009. The reversal of 1110100555001 is 1005550010111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 883695882601 + 226404672400 = 940051^2 + 475820^2 .

It is a cyclic number.

It is not a de Polignac number, because 1110100555001 - 222 = 1110096360697 is a prime.

It is a super-2 number, since 2×11101005550012 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1110100555009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555050277500 + 555050277501.

It is an arithmetic number, because the mean of its divisors is an integer number (555050277501).

Almost surely, 21110100555001 is an apocalyptic number.

It is an amenable number.

1110100555001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110100555001 is an equidigital number, since it uses as much as digits as its factorization.

1110100555001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 125, while the sum is 20.

Adding to 1110100555001 its reverse (1005550010111), we get a palindrome (2115650565112).

The spelling of 1110100555001 in words is "one trillion, one hundred ten billion, one hundred million, five hundred fifty-five thousand, one".