Base | Representation |
---|---|
bin | 10000001001110111110… |
… | …001011011110010011011 |
3 | 10221010101112201021212122 |
4 | 100021313301123302123 |
5 | 121142001404304242 |
6 | 2205551123331455 |
7 | 143126404615442 |
oct | 20116761336233 |
9 | 3833345637778 |
10 | 1110111009947 |
11 | 3988827a7465 |
12 | 15b191b20b8b |
13 | 808b57926b4 |
14 | 3ba30285d59 |
15 | 1dd2348aad2 |
hex | 10277c5bc9b |
1110111009947 has 2 divisors, whose sum is σ = 1110111009948. Its totient is φ = 1110111009946.
The previous prime is 1110111009929. The next prime is 1110111010051. The reversal of 1110111009947 is 7499001110111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1110111009947 is a prime.
It is not a weakly prime, because it can be changed into another prime (1110111002947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555055504973 + 555055504974.
It is an arithmetic number, because the mean of its divisors is an integer number (555055504974).
Almost surely, 21110111009947 is an apocalyptic number.
1110111009947 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110111009947 is an equidigital number, since it uses as much as digits as its factorization.
1110111009947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 35.
The spelling of 1110111009947 in words is "one trillion, one hundred ten billion, one hundred eleven million, nine thousand, nine hundred forty-seven".
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