Base | Representation |
---|---|
bin | 10000001001110111110… |
… | …001011110100000111001 |
3 | 10221010101112201212012012 |
4 | 100021313301132200321 |
5 | 121142001410133423 |
6 | 2205551123455305 |
7 | 143126404663133 |
oct | 20116761364071 |
9 | 3833345655165 |
10 | 1110111021113 |
11 | 398882804896 |
12 | 15b191b27535 |
13 | 808b57977c3 |
14 | 3ba3028a053 |
15 | 1dd2348e078 |
hex | 10277c5e839 |
1110111021113 has 2 divisors, whose sum is σ = 1110111021114. Its totient is φ = 1110111021112.
The previous prime is 1110111021091. The next prime is 1110111021121. The reversal of 1110111021113 is 3111201110111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 824267883664 + 285843137449 = 907892^2 + 534643^2 .
It is an emirp because it is prime and its reverse (3111201110111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1110111021113 - 210 = 1110111020089 is a prime.
It is not a weakly prime, because it can be changed into another prime (1110111021193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555055510556 + 555055510557.
It is an arithmetic number, because the mean of its divisors is an integer number (555055510557).
Almost surely, 21110111021113 is an apocalyptic number.
It is an amenable number.
1110111021113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110111021113 is an equidigital number, since it uses as much as digits as its factorization.
1110111021113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 14.
Adding to 1110111021113 its reverse (3111201110111), we get a palindrome (4221312131224).
The spelling of 1110111021113 in words is "one trillion, one hundred ten billion, one hundred eleven million, twenty-one thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •