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111011122101307 is a prime number
BaseRepresentation
bin11001001111011011001010…
…011111111011110000111011
3112120001120002222011111100011
4121033123022133323300323
5104022301234224220212
61032033445551322351
732245201043544121
oct3117331237736073
9476046088144304
10111011122101307
113240a60941044a
121054a8482203b7
1349c33c4875b1c
141d5ad7755d911
15cc79c25d64a7
hex64f6ca7fbc3b

111011122101307 has 2 divisors, whose sum is σ = 111011122101308. Its totient is φ = 111011122101306.

The previous prime is 111011122101199. The next prime is 111011122101317. The reversal of 111011122101307 is 703101221110111.

It is a strong prime.

It is an emirp because it is prime and its reverse (703101221110111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111011122101307 - 211 = 111011122099259 is a prime.

It is a super-2 number, since 2×1110111221013072 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111011122101317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55505561050653 + 55505561050654.

It is an arithmetic number, because the mean of its divisors is an integer number (55505561050654).

Almost surely, 2111011122101307 is an apocalyptic number.

111011122101307 is a deficient number, since it is larger than the sum of its proper divisors (1).

111011122101307 is an equidigital number, since it uses as much as digits as its factorization.

111011122101307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 22.

Adding to 111011122101307 its reverse (703101221110111), we get a palindrome (814112343211418).

The spelling of 111011122101307 in words is "one hundred eleven trillion, eleven billion, one hundred twenty-two million, one hundred one thousand, three hundred seven".